python get command line arguments

import sys
print("This is the name of the script:", sys.argv[0])
print("Number of arguments:", len(sys.argv))
print("The arguments are:" , str(sys.argv))

#Example output
#This is the name of the script: sysargv.py
#Number of arguments in: 3
#The arguments are: ['sysargv.py', 'arg1', 'arg2']

# Python program to demonstrate
# command line arguments
 
 
import getopt, sys
 
 
# Remove 1st argument from the
# list of command line arguments
argumentList = sys.argv[1:]
 
# Options
options = "hmo:"
 
# Long options
long_options = ["Help", "My_file", "Output="]
 
try:
    # Parsing argument
    arguments, values = getopt.getopt(argumentList, options, long_options)
     
    # checking each argument
    for currentArgument, currentValue in arguments:
 
        if currentArgument in ("-h", "--Help"):
            print ("Displaying Help")
             
        elif currentArgument in ("-m", "--My_file"):
            print ("Displaying file_name:", sys.argv[0])
             
        elif currentArgument in ("-o", "--Output"):
            print (("Enabling special output mode (% s)") % (currentValue))
             
except getopt.error as err:
    # output error, and return with an error code
    print (str(err))

import argparse

if __name__ == '__main__':
   parser = argparse.ArgumentParser()
   parser.add_argument('--arg1')
   parser.add_argument('--arg2')
   args = parser.parse_args()

   print(args.arg1)
   print(args.arg2)

   my_dict = {'arg1': args.arg1, 'arg2': args.arg2}
   print(my_dict)